(x^2-2x+1)(x+2)=0

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Solution for (x^2-2x+1)(x+2)=0 equation: 


Simplifying
(x2 + -2x + 1)(x + 2) = 0

Reorder the terms:
(1 + -2x + x2)(x + 2) = 0

Reorder the terms:
(1 + -2x + x2)(2 + x) = 0

Multiply (1 + -2x + x2) * (2 + x)
(1(2 + x) + -2x * (2 + x) + x2(2 + x)) = 0
((2 * 1 + x * 1) + -2x * (2 + x) + x2(2 + x)) = 0
((2 + 1x) + -2x * (2 + x) + x2(2 + x)) = 0
(2 + 1x + (2 * -2x + x * -2x) + x2(2 + x)) = 0
(2 + 1x + (-4x + -2x2) + x2(2 + x)) = 0
(2 + 1x + -4x + -2x2 + (2 * x2 + x * x2)) = 0
(2 + 1x + -4x + -2x2 + (2x2 + x3)) = 0

Combine like terms: 1x + -4x = -3x
(2 + -3x + -2x2 + 2x2 + x3) = 0

Combine like terms: -2x2 + 2x2 = 0
(2 + -3x + 0 + x3) = 0
(2 + -3x + x3) = 0

Solving
2 + -3x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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